Solution of the equation ${4.9^{x - 1}} = 3\sqrt {({2^{2x + 1}})} $ has the solution
$3$
$2$
$1.5$
$2/3$
${a^{m{{\log }_a}n}} = $
The number of integers $q , 1 \leq q \leq 2021$, such that $\sqrt{ q }$ is rational, and $\frac{1}{ q }$ has a terminating decimal expansion, is
The square root of $\frac{(0.75)^3}{1-(0.75)}+\left[0.75+(0.75)^2+1\right]$ is
${{12} \over {3 + \sqrt 5 - 2\sqrt 2 }} = $
If ${a^x} = {b^y} = {(ab)^{xy}},$ then $x + y = $